How can its diagonal be perpendicular to one of its sides? Since this can be read out of your details! You know point A and C are not adjacent but C and D are. So, AC must be the diagonal which is never perp. to any of the sides (CD)
Set equations for both containers:
Condition one: $y=2x$
Condition two: $(y-3)=4.5(x-2)$
plug in $y$ from condition one into the second equation:
$2x-3=4.5x-9$
simplify gives: $2.5x=6$
$\boxed{x=2.4}$
$\boxed{y=4.8}$
Answer:
y+3 = -6(x+9)
Step-by-step explanation:
m(x-x1)= (y-y1)
-6[x-(-9)] = [y-(-3)]
-6(x+9) = y+3
.....
Hey!
First, let's write the problem.
Multiply
with
.
Subtract
from both sides.
Divide both sides by
.
Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish