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2 years ago

What is the average power output pf a weight lifter who can lift 250 kg 2.0 m in 2.0 s

Physics

1 answer:

liq [111]2 years ago

8 0

Answer:

Power = 2.45Kw or 2450 Watts.

Explanation:

Given the following data;

Mass, m = 250kg

Height, h = 2m

Time, t = 2secs

We know that acceleration due to gravity, g is equal to 9.8m/s²

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

$Power = \frac {Energy}{time}$

But Energy = mgh

Substituting into the equation, we have

$Power = \frac {mgh}{time}$

$Power = \frac {250*9.8*2}{2}$

$Power = \frac {4900}{2}$

Power = 2450 Watts

To convert to kilowatt (Kw), we would divide by 1000

Power = 2450/1000

Power = 2.45Kw.

Therefore, the average power output of the weightlifter is 2.45 Kilowatts.

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what will be the restoring force if a spring with a spring constant of 45 newtons per meter is pulled 0.30 meters in the downwar

Anna35 [415]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices the can be found elsewhere:

A.) 14 newtons upward
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7 0

2 years ago

Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

tester [92]

Answer: $40\ N/C$

Explanation:

Given

Magnitude of charge is $q=0.5\ C$

Force experienced is $F=20\ N$

Electric field intensity is the electrostatic force per unit charge

$\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C$

Thus, the electric field intensity is $40\ N/C$

6 0

2 years ago

Thank you so muchhhhh

loris [4]

Answer:

I'm taking a wild guess at c

Explanation:

c. winter solstice

6 0

2 years ago

Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?

ozzi

Answer: The forces acting on both of them will increase in magnitude.

Explanation:

According to Coulomb's law, the electrostatic force between two bodies is proportional to the product of their two charges. If the charge on A is increased this product increases in size (it must have been non-zero to begin with, since there was a force between them at first). Thus, the force between them rises.

6 0

2 years ago

A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I

Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = $\frac{4\times \pi^2\times r^3}{GM}$ where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM

GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

20 = 3.96 X 10¹⁴ / R²

R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

8 0

2 years ago