Answer:
The upper limit of metamorphism occurs at the pressure and temperature of wet partial melting of the rock in question. Once melting begins, the process changes to an igneous process rather than a metamorphic process. During metamorphism the protolith undergoes changes in texture of the rock and the mineral make up of the rock.
Explanation:
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Answer:
10 Kg
Explanation:
Force is equal to mass times acceleration
therefore mass is equal to force divided by acceleration
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Answer:
The coupled velocity of both the blocks is 1.92 m/s.
Explanation:
Given that,
Mass of block A,
Initial speed of block A,
Mass of block B,
Initial speed of block B,
It is mentioned that if the two blocks couple together after collision. We need to find the common velocity immediately after collision. We know that due to coupling, it becomes the case of inelastic collision. Using the conservation of linear momentum. Let V is the coupled velocity of both the blocks. So,
So, the coupled velocity of both the blocks is 1.92 m/s. Hence, this is the required solution.
Answer:
1.55 N
Explanation:
Density = mass / volume
0.789 g/mL = m / 200.0 mL
m = 157.8 g
Weight = mass × acceleration due to gravity
W = (0.1578 kg) (9.8 m/s²)
W = 1.55 N
Answer:
8.91 J
Explanation:
mass, m = 8.20 kg
radius, r = 0.22 m
Moment of inertia of the shell, I = 2/3 mr^2
= 2/3 x 8.2 x 0.22 x 0.22 = 0.265 kgm^2
n = 6 revolutions
Angular displacement, θ = 6 x 2 x π = 37.68 rad
angular acceleration, α = 0.890 rad/s^2
initial angular velocity, ωo = 0 rad/s
Let the final angular velocity is ω.
Use third equation of motion
ω² = ωo² + 2αθ
ω² = 0 + 2 x 0.890 x 37.68
ω = 8.2 rad/s
Kinetic energy,
K = 0.5 x 0.265 x 8.2 x 8.2
K = 8.91 J