The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
The answer is 64. Hope it helps you
Answer:
C. 3.33 hours
Step-by-step explanation:
Use the algebra work equation:
= 
+ 
, where tb is the time to work together, t1 is the time it takes one person, and t2 is the time it takes the other person
Plug in the values we know:
= 
+ 
= 
+ 
= 
20 = 6tb
3.33 = tb
So, it would take them 3.33 hours when working together.
Answer:
8 were yoused because 8 times 3 =24 so if you subtract you get 8
Step-by-step explanation:
