Answer:
1+tan2x
Tan2x
= <u> sec²x </u> = <u>Sec²x </u> = cosec²x
Tan²x ( Sec²x/cosec²x)
Step-by-step explanation:
Answer:
—6
Explanation:
In an expression with a negative number and a positive number, the negative will come on top. This meaning the product (end piece) will be negative. In this problem despite the signs we know 3•2 is 6. Now since one number is negative (3) and the other is positive (2) negative will come out on top.
* KEEP IN MIND *
+ and + = positive
- and + = negative
Easy Memo for Multiplication and Divison:
“Same sign add, different sign subtract”
Add = Positive (+)
Subtract = Negative (-)
Answer:
- <u>Question 1:</u> <u />
<u />
- <u>Question 2:</u> <u />
<u />
- <u>Question 3:</u> <u />
<u />
- <u>Question 4:</u> <u />
Explanation:
<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>
<u></u>
a) By definition:
b) Given:
c) By substitution:
<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>
a) <u>Separate variables</u>
b)<u> Integrate</u>
c) <u>Antilogarithm</u>
<u>Question 3. Which particular solution matches the additional information?</u>
<u></u>
Use the measured rate of 4 grams per hour after 3 hours
First, find the mass at t = 3 hours
Now substitute in the general solution of the differential equation, to find A:
Round A to 1 significant figure:
<u>Particular solution:</u>
<u>Question 4. What was the mass of the bacteria at time =0?</u>
Substitute t = 0 in the equation of the particular solution:
Answer:
y = 89 x = 123
Step-by-step explanation:
since they're both in standard form, its easier to do the process of elimination
x - y = 34
-x -y -212
------------------
-2y = -178
y = 89
now plug in y to any one of those two equations
x - y = 34
x - 89 = 34
x = 123
<em>to check:</em>
<em>x</em><em> </em><em>+</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>
<em>1</em><em>2</em><em>3</em><em> </em><em>+</em><em> </em><em>8</em><em>9</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>
<em>2</em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>