Let the 3-digit palindrome be 101a+10b. a+a+ab=8+b, so 2a+ab-b=8. 2a+b(a-1)=8; b=2(4-a)/(a-1). From this we know that a > 1. And we know 4-a > 0 so a < 4. This limits a to 2 and 3 which make b=4 and 1. The palindromes are 242 and 313.
as the function is polynomial domain exist for all real number ie (-infinity to + infinity) but range exist (0 to +infinity ) due to modulus negetive range do not exist
