2/3 is <u>400%</u> of 1/6
0.2 is <u>12.5%</u> of 1 3/5
<h3>Calculating Percentages</h3>
From the question, we are to determine what percent of 1/6 is 2/3
Let the value be x
Thus,
We can write that
2/3 is x% of 1/6
This means
2/3 = x/100 × 1/6
Now, solve for x
2/3 = x/100 × 1/6
2/3 = x/600
x = (2×600)/3
x = 400
Hence, 2/3 is 400% of 1/6
We are to determine what percent of 1 3/5 is 0.2
Let the value be y
That is,
0.2 is y% of 1 3/5
This can be written as
0.2 = y% × 1.6
0.2 = y/100 × 1.6
Now, solve for y
0.2 = y/100 × 1.6
0.2 = 1.6y/100
1.6y = 0.2 × 100
1.6y = 20
y = 20/1.6
y = 12.5
Hence, 0.2 is 12.5% of 1 3/5
Learn more on Calculating Percentages here: brainly.com/question/843074
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Answer:
88
Step-by-step explanation:
i used 1980 and 1985. I subtracted 42.1 by 33.4, got 8.7, divided that by 5 since theres been 5 years since, then multiplied by 6 since theres a 6 year difference from 2005 and 2011, then added them.
Answer:
a ) x = - 3, y = 5
x = 0, y = 2
x = 5, y = - 3
b ) you should draw the line by marking the coordinates in the graph, then draw a straight line passing through all those three points.
Step-by-step explanation:
y = 2 - x
When x = - 3,
y = 2 - x
= 2 - ( - 3 )
= 2 + 5
y = 7
When x = 0,
y = 2 - x
= 2 - 0
y = 2
When x = 5,
y = 2 - x
= 2 - 5
y = - 3
b ) you should draw the line by marking the coordinates in the graph, then draw a straight line passing through all those three points.
Answer:
X = 2 or X = -10
Step-by-step explanation:
We know either3x+12=18or3x+12=−18
3x+12=18(Possibility 1)
3x+12−12=18−12(Subtract 12 from both sides)
3x=6
3x
3
=
6
3
(Divide both sides by 3)
x=2
3x+12=−18(Possibility 2)
3x+12−12=−18−12(Subtract 12 from both sides)
3x=−30
3x
3
=
−30
3
(Divide both sides by 3)
x=−10
Answer:
x=2 or x=−10
To be precise, the size of your sample space is <span><span>(<span>2410</span>)</span><span>(<span>2410</span>)</span></span>. This number does go on the bottom of the fraction, and what goes on top is the size of the event. Break up the event into independent events 1. choose the 2 defective bulbs, and 2. choose the remaining 8 bulbs. I don't have much choice in event 1. There is only one way to choose both of the defective balls. In other words, <span><span>(<span>22</span>)</span><span>(<span>22</span>)</span></span> (choosing 2 defective bulbs from a set of 2 defective bulbs). For event 2, there are <span><span>24−2=22</span><span>24−2=22</span></span> nondefective bulbs, and I must choose <span>88</span> of them, so that's <span><span>(<span>228</span>)</span><span>(<span>228</span>)</span></span>. Finally, since events 1 and 2 are independent, we multiply the answers for the combined event: <span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span></span>
<span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span></span>
Or, since <span><span><span>(<span>22</span>)</span>=1</span><span><span>(<span>22</span>)</span>=1</span></span>,
<span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span></span>
Hope this helps!
