Answer:
She didn't take the LCM, made an error while cross multiplying
x = -6
Step-by-step explanation:
a)she didn't take the LCM before cross multiplying.
Also, didn't cross multiply correctly
b) 1 -2/(x-2) = (x+1)/(x+2)
1 - 2/(x-2) = (x+2-1)/(x+2)
1 - 2/(x-2) = 1 - 1/(x+2)
1 - 2/(x-2) = 1 - 1/(x+2)
-2(x+2) = -1(x-2)
-2x-4 = -x+2
x = -6
A square is a figure with four equal sides and four right angles.In a square the diagonals bisect at right angles .
In the above given options option A is the right answer.
If the diagonals of any parallelogram are perpendicular then the figure is not necessarily a square.
Diagonals are perpendicular in a rhombus too.
A square and Rhombus both have diagonals that are perpendicular.
So it is not a necessary condition for a parallelogram to be a square .
The other options are right .
So option B is the right option that if diagonals are perpendicular is not sufficient to prove the figure to be a square.
0.123655913978495
Hope this helps :))
F(2)+g(4)
evaluate them seperately
f(2)=2+2=4
g(4)=10(4)-4
g(4)=40-4
g(4)=36
f(2)+g(4)=4+36=40
You factor this out. So x+2x^(1/2)-63. Factors into (x^(1/2)+9)(x^(1/2)-7). If you distribute it, you can see it gives you your original equation
