Answer:
Explanation:
A. Using
E= ma/q
E=m/q(2s/t²)
So
E= 9.1x10^-31/1.6*10^-19( 2*4.5/ 3*10-12)
E=5.7NC
The electric field has to be downward since the force is positive that is upward
B.
The electron acceleration is of the order of 10^11 times greater so for practical purposes we neglect the effect of gravity
A) Vi= 60 m/s
a= -9.81 m/s^2
Vf= 0m/s^2
d=?
Vf^2=Vi^2+2ad
(0m/s)^2=(60m/s)^2+2(-9.81m/s^2)d
0=3600+(-19.62)d
-3600=(-19.62)d
(-3600)/(-19.62)=(-19.62)d/(-19.62)
d=183.5m
c) Vi= 60 m/s
a= -9.81 m/s^2
Vf= 0m/s^2
t=10s
d=?
d=Vi*t+(1/2)a*t^2
d=60m/s(10s)+(1/2)(-9.81m/s^2)(10s)^2
d=600+(-4.905)(100)
d=600+(-490.5)
d=108.5m