Solve for a: 2a + 8b = 4c
2 answers:
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Notice the graph, the domain is just the horizontal area "used up" over the x-axis, so, the graph goees from ![\bf -\cfrac{5x}{2}\quad to\quad \cfrac{5x}{2}\implies domain\implies \left[-\cfrac{5x}{2}\ ,\ \cfrac{5x}{2}\right]](https://tex.z-dn.net/?f=%5Cbf%20-%5Ccfrac%7B5x%7D%7B2%7D%5Cquad%20to%5Cquad%20%5Ccfrac%7B5x%7D%7B2%7D%5Cimplies%20domain%5Cimplies%20%5Cleft%5B-%5Ccfrac%7B5x%7D%7B2%7D%5C%20%2C%5C%20%20%20%5Ccfrac%7B5x%7D%7B2%7D%5Cright%5D)
the range is just, the vertical area "used up" over the y-axis, so, the graph goes to 2 and down to -2, thus![\bf range\implies [2\ ,\ -2]](https://tex.z-dn.net/?f=%5Cbf%20range%5Cimplies%20%5B2%5C%20%2C%5C%20-2%5D)
the range is just, the vertical area "used up" over the y-axis, so, the graph goes to 2 and down to -2, thus