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2 years ago

If m ZA = 87º and mZB = 32°, find m21.

Mathematics

1 answer:

BaLLatris [955]2 years ago

6 0

Answer:

Step-by-step explanation:

∠1 = ∠A + ∠B

{ exterior angle equals the sum of opposite interior angles }

= 87 + 32

= 119

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Which fraction is bigger 7/8 or 14/15 using lcm

Sever21 [200]

Between 7/8 and 14/15 the bigger value is the 7/8. When comparing to fractions you need look on the denominator of the fractions the smaller the denominator the larger the fraction. Thank you for posting your question here. Hope it helps.

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2 years ago

Write the simplified expression: 2x + 3(x - 2) - 3(x -6)

Bas_tet [7]

Answer:

2x+12

Step-by-step explanation:

2x+3(x−2)−3(x−6)

Distribute:

=2x+(3)(x)+(3)(−2)+(−3)(x)+(−3)(−6)

=2x+3x+−6+−3x+18

Combine Like Terms:

=2x+3x+−6+−3x+18

=(2x+3x+−3x)+(−6+18)

=2x+12

Answer:

=2x+12

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2 years ago

Read 2 more answers

How do i express 11/20 as a percent??

Reptile [31]

So since a percent is out of 100 you would put 11/20 and right an equal sign next to that and the bottom fraction would be x/100. Then you would find the relationship between 100 and 20. 20 times 5 is 100 so then 11 times 5 is 55. 55% is your answer

3 0

2 years ago

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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts

Hunter-Best [27]

Answer:

The value of the test statistic is $t = 2.1$

Step-by-step explanation:

Our test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected value, $\sigma$ is the standard deviation and n is the size of the sample.

The level of ozone normally found is 7.5 parts/million (ppm).

This means that $\mu = 7.5$

The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7.

This means that $X = 7.8, \sigma = 0.7, n = 24$

Test Statistic:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{7.8 - 7.5}{\frac{0.7}{\sqrt{24}}}$

$t = 2.1$

The value of the test statistic is $t = 2.1$

7 0

2 years ago

Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads

Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

$Distance = Speed \times Time$

$Distance\ OA = 10 \times 2.5 = 25\ km$

$Distance\ OB = 16 \times 2.5 = 40\ km$

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled $\triangle AOB$ .

According to Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km$

The speed at which distance is increasing between the two boats is given as:

$\dfrac{47.17}{2.5} \approx 18.87\ km/hr$

4 0

2 years ago