Answer:
The vertex form is: y = 3(x-2)^2 + 7
. The vertex is (2, 7)
Step-by-step explanation:
Write the function: y = 3x^2 - 12x + 11 in vertex form
The vertex form of a quadratic equation is:
y = m(x - a)^2 + b where (a,b) is the vertex
For y = 3x^2 - 12x + 11
Solve for m
y = 3(x^2 - 4x) + 11
Complete the Square:
y = 3(x^2 - 4x + 4) + 11 - 4
y = 3(x - 2)^2 + 7
The vertex then is (2, 7)
3x+5=19
-5 -5
3x=14
/3 /3
x= 4 2/3
Whether dividing constant terms or polynomials, we always have definitive terms when it comes to division. Suppose we say, 10x divided by 2. The dividend is the 10x and the divisor is the 2. In other words, the dividend is the number to be divided by the divisor, to obtain the answer called the quotient.
When dividing polynomials, your main goal is to be able to divide the dividend evenly into the <em>divisor</em>. For example, we divide x²+2x+1 by x+1. The first thing you're going to focus is, what term will completely divide the first term of the polynomial? That would be x. Why? Because when you multiply x with x+1, the product is x²+x. When you subtract this from the polynomial, the x² will cancel out. All you have to do is subtract x from 2x, yielding x. Then, you carry down the last term of the equation: +1. You do the steps again. The term that will completely divide x+1 by x+1 is 1. When you subtract the two, you will come up with zero. That means there is no remainder. The polynomial is divisible by the divisor.
x + 1
------------------------------------
x+1| x²+2x+1
- x²+x
----------------------
x +1
- x +
------------
0
Construct the perpendicular bisector of one side of triangle
Construct the perpendicular bisector of another side
Where they cross is the center of the Circumscribed circle
Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle!
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