L(which is length) is equal to 42 divided by width which is 6. so the equation is L=42/6
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<u>ANSWER: </u>
x-intercepts of
<u>SOLUTION:</u>
Given, -- eqn 1
x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.
Now, let us find the zeroes using quadratic formula for f(x) = 0.
Here, for (1) a = 1, b= 12 and c = 24
Hence the x-intercepts of
Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].
So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).
There is one tangent at x = 1. It is x = 1 (a vertical line).
There is no tangent at x = 35, because the original equation has no solution at x = 35.