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2 years ago

I think of a number multiply it by 4 and subtract 3 i get 11

Mathematics

2 answers:

Ipatiy [6.2K]2 years ago

8 0

Answer:

3.5

Step-by-step explanation:

Let the number be x.

x × 4 - 3 = 11

4x - 3 = 11

Add 3 on both sides.

4x - 3 + 3 = 11 + 3

4x = 14

Divide both sides by 4.

4x/4 = 14/4

x = 14/4

x = 7/2

Bond [772]2 years ago

5 0

Answer:

Solution,

Let the number be X

$x \times 4 - 3 = 11 \\ or \: 4x - 3 = 11 \\ or \: 4x = 11 + 3 \\ or \: 4x = 14 \\ or \: x = \frac{14}{4} \\ x = 3.5$

Hope this helps...

Good luck on your assignment..

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Antoine has $13 in his checking account. He buys some school supplies and ends up with $5 in his account. what was the overall c

ladessa [460]

13-5 is how you would do this so your answer would be 8 :)

6 0

2 years ago

Find a solution to the inequality x > 4.<br> A. 8<br> B. 3<br> C. 4<br> D. 0

ella [17]

Answer:

Step-by-step explanation:

Isn't it simple because all other numbers are less than 4?

3 0

1 year ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

2 years ago

A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an

lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of $v_2=613.87m/sec$

Step-by-step explanation:

We have given internal diameter of the garden hose $d_1=0.740in=1.8796cm$

So radius $r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm$

So area $A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2$

Water in the hose has a speed of 4 ft/sec

So $v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)$

Number of holes n = 36

Diameter of each hole $d_2=0.1397cm$

So radius $r_2=0.0698cm$

So area $A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2$

From continuity equation

$A_1v_1=nA_2v_2$

$2.7733\times 121.92=36\times 0.0153\times v_2$

$v_2=613.87m/sec$

7 0

2 years ago

Solve the system of equations using substitution

Andru [333]

Answer:

x = 136/11 , y = 68/11

Step-by-step explanation:

Solve the following system:

{6 x - y = 68

2 y = x

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{6 x - y = 68

2 y = x

Hint: | Reverse the equality in 2 y = x in order to isolate x to the left hand side.

2 y = x is equivalent to x = 2 y:

{6 x - y = 68

x = 2 y

Hint: | Perform a substitution.

Substitute x = 2 y into the first equation:

{11 y = 68

x = 2 y

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for y:

{11 y = 68

x = 2 y

Hint: | Solve for y.

Divide both sides by 11:

{y = 68/11

x = 2 y

Hint: | Perform a back substitution.

Substitute y = 68/11 into the second equation:

{y = 68/11

x = 136/11

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = 136/11 , y = 68/11

7 0

2 years ago