The piecewise function all the way to the left (x + 3) should have an ending point shaded in. [At x = -2] The next function ((x^2) -1) should have both ending points left unshaded. Finally, the logarithm function should have a shaded in starting point [At x = 1] and should have an unshaded ending point at x = 3.
To what?? Please explain.
Answer:
C. Yes Devon should have evaluated f(3).
Step-by-step explanation:
She substituted the wrong value. For x - 3 to be a factor f(3) must equal 0.
f(3) = 3^3 + 3^2 - 10(3) + 8 = 27 + 9 - 30 + 8
= 14, so x- 3 is not a factor anyway but she did substitute the wrong value.
Answer:
hehe ily tacos hehehhee
Step-by-step explanation:
