Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
Answer:
A
Step-by-step explanation:
Answer:
2x +2x=90
ZRQ
Step-by-step explanation:
FOR THE FIRST ONE, SUM OF ANGLES IN A TRIANGLE IS 180 AND SINCE WE KNOW ONE ANGLE IS 90° THE REST WOULD ADD UPTO 90°
THE SECOND ONE, JUST FOLLOW THE SEQUENCE OF THE MARKED LINES
for XYZ they went from the unlabeled line to the double marked line to the single marked line. similarly go for ZRQ