56a. 3000(1+.06)^5= 4014.67
56b. 3000(1+(.06/2))^5= 3477.82
56c. 3000(1+(.06/12))^5= 3075.75
56d. 3000e^(0.06•5)= 4049.57
58a. When placed in a scientific calculator and finding the ExpReg, you get the equation 50•2.828^x, so you take 2.828 and turn that in to a percentage so it’ll be about 2.83%.
58b. 50
58c. 50•2.828^t
58d. 50•2.828^4.5= about 5,378 bacteria
58e. Putting the equation and 50,000 into a graphing calcultor and finding the intersect of their graphs shows that after about 6.64 hours, the bacteria will reach that number.
59a. Set the equation to 150,000 (the triple of 50,000) and solve it, so it’ll start off as 50,000(1+(0.075/4))^x=150,000. The answer will be about 59.1 years.
59b. Do the same as the last question, except with the equation 50,000e^(0.075•x). The answer will be about 14.6 years.
Answer:
Multiple across equal sign (Denominator x Nominator and vise versa)
(40+80) + (8+2)
120+10
130
your answer would be 130
you group 40 and 80 and get the answer and then group 8 and 2
get answer to both then and then you add them together for the answer
Answer:
-55
Step-by-step explanation:
2nd term=> -1 + -2 × (2 - 1)
3rd term=> -1 + -2 × (3 - 1)
:
28th term=> -1 + -2 × (28 - 1)
=> -1 - 54 = -55