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2 years ago

1. Segment A'B' is parallel to segment AB. What is the length of segment BB'?

Mathematics

1 answer:

ella [17]2 years ago

5 0

Answer:

A. 3.5

Step-by-step explanation:

Given that AB is parallel to A'B', therefore,

CB/CB' = CA/CA'

CB' = 7

CB = CB' + BB' = 7 + BB'

CA' = 6

CA = CA' + AA' = 6 + 3 = 9

Plug in the values

(7 + BB')/7 = 9/6

(7 + BB')/7 = 3/2

Cross multiply

2(7 + BB') = 7(3)

14 + 2BB' = 21

Subtract 14 from both sides

2BB' = 21 - 14

2BB' = 7

Divide both sides by 2

BB' = 7/2

BB' = 3.5

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Part 1

$6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)} \\ \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\ \\ =3$

Part 2

$7-8\div4(3^2-1)=7-8\div4(9-1) \\ \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\ \\ =6 \frac{1}{2} = \frac{13}{2}$

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Part 4

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Part 6

$12-11\cdot2+16\div8=12-22+2 \\ \\ =-8$

Part 7

$-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\ \\ =-2-(-1)=-2+1=-1$

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$7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\ \\ =7+(-7)\cdot5=7+(-35)=7-35 \\ \\ =-28$

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