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2 years ago

You push against a wall and the wall pushes back on you.

Physics

1 answer:

emmainna [20.7K]2 years ago

4 0

Answer:

Its the third law of motion.

Explanation:

Newton's third law of motion states that every action has equal and opposite reaction.

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Astronomers use many different pieces of equipment to study space: optical telescopes on Earth, space telescopes, and space prob

Kobotan [32]

Then it would be C if D has been eliminated

8 0

2 years ago

Read 2 more answers

When two objects made of different materials are rubbed together, they will attract each other after the charging process.Immers

Sergio039 [100]

Answer:

True

Explanation:

because their is friction(e.g take a ruler rub it in your hair then put it on top of a piece of paper on the table then u will see the process)among the two objects.

4 0

1 year ago

He chart below compares the characteristics of four objects, A, B, C, and D, discovered in the solar system.

Leto [7]

Answer:

Object A and C (Second choice)

Let's observe one by one

#A..

Kupier belt is a belt associated at Neptune outerside similar to asteroid belt

Hence it's correct

#B.

Has enough gravity to keep other objects far away from its orbit

It's any planet or may be sun /star

Is in orbit around the sun

Sure it's correct

Is almost circular in shape

It's any planet or moons

5 0

1 year ago

Select the correct answer.

Murrr4er [49]

Answer:

I will choose the answer A

3 0

2 years ago

What is the resistance of : A) A 1.70 m long copper wire that is 0.700 mm in diameter? B) A 20.0 cm long piece of carbon with a

astra-53 [7]

Answer:

(I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

Explanation:

Given that,

Length of copper wire = 1.70 m

Diameter = 0.700 mm

Length of carbon piece = 20.0 cm

Cross section area $A = (2.00\times10^{-3})^2\ m$

(I). We need to calculate the area of copper wire

Using formula of area

$A=\pi r^2$

$A=3.14\times(\dfrac{0.700\times10^{-3}}{2})^2$

We need to calculate the resistance

Using formula of resistance

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.68\times10^{-8}\times1.70}{3.14\times(\dfrac{0.700\times10^{-3}}{2})^2}$

$R=0.0742\ \Omega$

(II). We need to calculate the resistance

Using formula of resistance

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{3.5\times10^{-5}\times20\times10^{-2}}{(2.00\times10^{-3})^2}$

$R=1.75\ \Omega$

Hence, (I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

8 0

2 years ago