1. V = lwh
V = (8)(4)(5)
V = (32)(5)
V = 160 units³
2. V = lwh + lwh
V = (4)(2)(1) + (3)(1)(1)
V = (8)(1) + (3)(1)
V = 8 + 3
V = 11 units³
3. V = leh + s³
V = (9)(3)(4) + (3)³
V = (27)(4) + 27
V = 108 + 27
V = 135 units³
4. V = lwh
V = (3)(7)(2)
V = (21)(2)
V = 42 units³
Answer:
The table is attached!
Step-by-step explanation:
- 6 students play both musical instrument and a sport
- 3 students play neither a musical instrument nor a sport
- 14 students in total play a sport
Given: There are 24 students in the class
The number of students that does not play a sport is 24 - 14 = 10
The number of students that does not play a musical instrument but play a sport = 14 - 6 = 8
The frequency table thus is attached below:
Answer:
Step-by-step explanation:
Answer:
x²/9 − (y + 1)²/81 = 1
Step-by-step explanation:
-2y − 82 + 9x² = y²
9x² = y² + 2y + 82
9x² = y² + 2y + 1 + 81
9x² = (y + 1)² + 81
9x² − (y + 1)² = 81
x²/9 − (y + 1)²/81 = 1
Answer:
The ship is approximately 100 km to the Port.
Step-by-step explanation:
The sketch to the question gives a triangle with two sides and an included angle. Let the distance from the Port to the stopping point of the ship be represented by c. It can be determined by the application of cosine rule. Cosine rule states that:
= + -2ab Cos C
a = 50 km
b = 60 km
C = 51 + 80 =
So that;
= + -2(50 x 60) Cos
= 2500 + 3600 -6000 x -0.6561
= 6100 + 3936.6
= 10036.6
c =
= 100.183
c = 100.18 km
Thus, the ship is approximately 100 km to the Port.