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2 years ago

1. The vector v has a magnitude of 11 millimeters and a direction angle of 75 degrees. Write the component AND linear

Mathematics

1 answer:

aliina [53]2 years ago

4 0

Answer:

MAGNITUDE

Step-by-step explanation:

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If you buy a car for 15500 an average on an average a new car loses 11% of its value the moment that is driven off the lot once

AfilCa [17]

Answer:

$13,795

Step-by-step explanation:

15500/x=100/11

(15500/x)*x=(100/11)*x - we multiply both sides of the equation by x

15500=9.0909090909091*x - we divide both sides of the equation by (9.0909090909091) to get x

15500/9.0909090909091=x

1705=x

x=1705

now we have:

11% of 15500=1705

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2 years ago

Select the correct name for the following line.

Pani-rosa [81]

The correct name for the line shown is the answer choice C.

It can be A because the picture is a line not a ray and it cant be B because the picture shown is not a segment

Hope this helps :)

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2 years ago

Read 2 more answers

Lena purchased a prepaid phone card for $20. Long distance calls cost 21 cents a minute using this card, Lena used her card only

slega [8]

<u>Answer:</u>

37 minutes

<u>Step-by-step explanation:</u>

Lena has 20 dollars. 20 - 12.23 = 7.77

Lena has $7.77 dollars left.

We divide this by .21 to see how many minutes her call was.

7.77 ÷ .21 = 37

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5 0

2 years ago

7. What polynomial remains after the greatest common factor is factored out of the

lara31 [8.8K]

Answer:the answer is A

Step-by-step explanation:

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2 years ago

Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the even

Allushta [10]

Answer:

$P(E|A)= \frac{10}{11}$

Step-by-step explanation:

Given

Two rolls of die

$E \to$ one of the outcomes is 6

$A \to$ atleast one is 6

Required

P(E|A)

First, list out the outcome of each

$E = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

So:

$P(E|A)= \frac{n(E\ n\ A)}{n(A)}$

Where:

$E\ n\ A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$n(E\ n\ A) = 10$

$n(A) = 11$

So:

$P(E|A)= \frac{10}{11}$

7 0

2 years ago