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2 years ago

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1.- Que distancia recorrió una carga de 2,5x10-6 coul, generando así un campo eléctrico de 55new/coul.

1 answer:

sergiy2304 [10]2 years ago

3 0

Answer:

r = 20.22 m

Explanation:

Given that,

Charge, $q=2.5\times 10^{-6}\ C$

Electric field, $E=55\ N/C$

We need to find the distance. We know that, the electric field a distance r is as follows :

$E=\dfrac{kq}{r^2}\\\\r=\sqrt{\dfrac{kq}{E}}\\\\r=\sqrt{\dfrac{9\times 10^9\times 2.5\times 10^{-6}}{55}}\\\\r=20.22\ m$

So, the required distance is 20.22 m.

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$a_r=\omega ^2\cdot r$

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2 years ago

An object undergoes two successive displacements:

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To find the magnitude of the net displacement, we have to resolve each of the two displacements into the horizontal and vertical direction first.

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2nd displacement is:

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Learn more about displacement:

brainly.com/question/3969582

#LearnwithBrainly

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