1. -18 +15x = 3(4x-6) + 3x
-18 + 15x = 12x - 18 + 3x
-18 + 3x = -18 + 3x
3x = 3x
x = All Real Numbers (because we don't know what x is since the equation is 3x = 3x, we can assume that it is all "real" numbers)
2. -10 + 5x = 5(x - 3) + 5
-10 + 5x = 5x - 15 + 5
-10 = -10
Answer Undefined (because the x coefficients canceled out, we don't know what x even is, so we can claim it as undefined.)
Hello,
If center is (0,0)
x²/a²+y²/b²=1 for a half horizontal axis of a, and a half vertical axis of b
Here
a=2 ==> a²=4
b=8 ==> b²=64
Answer:
(- 1, 1) and (- 5, - 35)
Step-by-step explanation:
since both equations express y in terms of x, equate the right sides
x² + 15x + 15 = - x² + 3x + 5 ( subtract - x² + 3x + 5 from both sides )
2x² + 12x + 10 = 0 ( divide all terms by 2 )
x² + 6x + 5 = 0 ← in standard form
(x + 1)(x + 5) = 0 ← in factored form
equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
x + 5 = 0 ⇒ x = - 5
substitute these values into either of the 2 equations and solve for y
x = - 1 : y = (- 1)² + 15(- 1) + 15 = 1 - 15 + 15 = 1 ⇒ (- 1, 1 )
x = - 5 : y = (- 5)² + 15(- 5) + 15 = 25 - 75 + 15 = - 35 ⇒ (- 5, - 35 )
None of the given options
Answer: The area common to both triangle is 31.77 sq. cm.
Step-by-step explanation:
Since we have given that
30-60-90 triangles are placed.
So, the ratio of sides would be
Since Hypotenuse = 12 cm
So, it becomes,
So, Base would be
and Perpendicular would be
So, Area common to the both triangles would be
Hence, the area common to both triangle is 31.77 sq. cm.
hopefully this will help ( ;