A) 8 - add up the how many numbers there are after the 4 on the left column
b) 41 - line up all of the numbers from least to greatest and find the middle number
c) 39 - do step b again but this time remove the oldest worker and add the younger one in
Well 41 divided by 6 is 6.8333333333333 so you just need to subtract .833333333333
I hope this answered your question
Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
Answer:
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Step-by-step explanation:
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