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2 years ago

123456-654321= eeeeee

Mathematics

1 answer:

BigorU [14]2 years ago

4 0

Answer:

−530865

Step-by-step explanation:

hoped I helped:)

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You have a loan for $200,000 at 8.5% annual simple interest. What is your monthly interest payment?

Sergeu [11.5K]

Answer:

c. 1,417

Step-by-step explanation:

200,000 (8.5%) = 17,000

17,000 / 12 = 1,416.67 or 1,417

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2 years ago

Look at pic please. :)

Vesna [10]

Answer:

$0.40 per minute

Step-by-step explanation:

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2 years ago

What is the least common den omit or of 12, 8, 36

bearhunter [10]

The least common denominator of 12, 8, and 36 is 72.

8 0

2 years ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

2 years ago

Why would I rewrite this

Ratling [72]

You are finding 3 1/6 - 1 5/6.

To solve, you should first change it so that the numerator of the first fraction is greater than the numerator of the second. Note that both have the same denominator (6). Subtract as usual:

3 1/6 = 2 7/6

2 7/6 - 1 5/6 = 1 2/6

1 2/6 is your answer.

7 0

2 years ago