$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Answer:
31.5 (multiplied it after)
Step-by-step explanation:
I love algebra anyways
The ans is in the picture with the steps how i got it
(hope this helps can i plz have brainlist :D hehe)
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
Answer:
20
Step-by-step explanation:
Subtract the 2 from the width of 7, and then multiply the height by the width.
4x5=20
*<em>The graph has an asymptote at y = 0 and is increasing as x approaches positive infinity.*</em>
(got it right on edmentum)
<h2>
for your assurance please look at the picture below for the right answer↓</h2>