To know how many times does the current oscillates in the given time, you take into account that the number of oscillation can be calculated by using the following expression:

$n=ft$ (1)

f: frequency of the oscillation of the current

t: time = 0.30s

The frequency is the number of cycles per second, that is, f = 60 cycles/s

You replace the values of f and t in the equation (1):

$n=(60\frac{cycles}{s})(0.30s)=18\ cycles$

In 0.30s the current oscillates 18 times

5 0

2 years ago

Write an equation that passes through the point (1, 3) and is perpendicular to x – 2y = -8.

Umnica [9.8K]

Answer:

y = -2x + 5

Step-by-step explanation:

Given:

Passes through point (1, 3)

Perpendicular to x – 2y = -8

Solve:

x – 2y = -8

y = 1/2x + 4

The slope is m = 1/2

The slope of the perpendicular line is the inverse of the slope of the original equation.

The slope of the inverse equation is m = -2.

Making an inverse equation of y = -2x + a

Find a:

Use point, (1, 3) where (x, y):

3 = (-2)*(1) + a

a = 5

y = -2x + 5

4 0

2 years ago

Read 2 more answers