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2 years ago

. How many grams of Na2SO4 are required to make 2700 mL of a 2.0 M solution?

Chemistry

2 answers:

ratelena [41]2 years ago

6 0

Answer:

Explanation:

From the net ionic equation

Ba2+(aq) + SO42-(aq) ==> BaSO4(s) we see that 1 mole Ba2+ reacts with 1 mole SO42- to -> 1 mol BaSO4

Find moles of Ba2+ used: 0.250 moles/L x 0.0323 L = 0.008075 moles Ba2+

Find moles SO42- present: 0.008075 moles Ba2+ x 1 mol SO42-/1 mol Ba2+ = 0.008075 mol SO42-

Find mass of Na2SO4 present: 0.008075 mol SO42- x 1 mol Na2SO4/1 mol SO42- x 142.04 Na2SO4/mole = 1.14698 g = 1.15 g Na2SO4 (to 3 significant figures)

Andru [333]2 years ago

6 0

Answer: Approx 2kg of salt are required.

Explanation: If 4.5 ⋅ L of a 3.0 ⋅ m o l ⋅ L − 1 solution are required, this is a molar quantity of 4.5 ⋅ L × 3.0 ⋅ m o l ⋅ L − 1 = 13.5 ⋅ m o l . Now, we simply multiply this molar quantity by a molar mass to get the mass: 13.5 ⋅ m o l × 142.04 ⋅ g ⋅ m o l − 1 = ? ? ⋅ g

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Give three examples,from the lab where potential energy was converted to kinetic energy?

creativ13 [48]

Answer:

*a car geared neutral that is at a stop. two men start pushing it

*tire physical therapy. trie is at rest until you come up to the tire and flip it

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Explanation:

everthing has to be at a complete stop then through energy be moved

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2 years ago

Sulfuric acid is formed when sulfur dioxide reacts with oxygen and water. Write a balanced chemical equation for the reaction. (

Nesterboy [21]

Balanced chemical equation for the reaction is:

2S $O_{2}$ (g) + $O_{2}$ (g)+ 2 $H_{2}$ O (l) ⇒ $H_{2} S_{} O_{4}$

Moles of $H_{2} S_{} O_{4}$ formed is 5.75 moles.

Moles of oxygen used is 5.75 moles in the reaction.

Explanation:

Data given:

moles of S $O_{2}$ = 11.5 moles

moles of $H_{2} S_{} O_{4}$ = ?

Moles of $O_{2}$ needed =?

balanced equation with states of matter =?

Balanced chemical reaction under STP condition is given as:

2S $O_{2}$ (g) + $O_{2}$ (g) + 2 $H_{2}$ O (l) ⇒ $H_{2} S_{} O_{4}$

From the balanced reaction 2 moles of sulphur dioxide reacted to form 1 mole of sulphuric acid:

so, from 11.5 moles of S $O_{2}$ , x moles of $H_{2} S_{} O_{4}$ is formed

$\frac{1}{2} =\frac{x}{11.5}$

2x = 11.5

x = 5.75 moles of sulphuric acid formed.

From the balanced reaction 1 mole of oxygen reacted to form 1 mole of sulphuric acid.

when 11.5 moles of Sulphur dioxide reacted then oxygen in the reaction is 5.75 moles.

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2 years ago

What is a reaction rate?

kondaur [170]

Answer:

A reaction rate is a measure of how fast a reactant disappears or a product forms during a reaction.

Explanation:

It is usually defined as the change in concentration per unit time:

Δ(concentration)/Δt

The units are (moles per litre) per second.

In symbols, the units are mol/(L·s) or mol·L^-1 s^-1.

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2 years ago

the latest weather report includes the following statement: the temperature is 78°f, barometric pressure is 29 and the relative

NeX [460]

Answer:

Explanation:

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2 years ago

When dilute HCL is added to zinc pieces taken in a test tube

Romashka-Z-Leto [24]

Answer:

zince chloride will be formed and hydrogen gas will be librated.

Explanation:

When dilute HCl is added to zinc pieces, a rection will takes place as follows :

$Zn+HCl\rightarrow ZnCl_2+H_2$

It means that zinc chloride will form when zinc reacts with dilute HCL. Also hydrogen gas will produced.

As zinc is more reactive than hydrogen, it displaces hydrogen from its solution and forms zinc chloride. The form product is white in color and H₂ is an odorless gas.

Hence, zince chloride will be formed and hydrogen gas will be librated.

6 0

2 years ago