Ask question

Ask question

All categories

PSYCHO15rus [73]

2 years ago

11

A motorcycle is moving at a constant velocity of 15 meters/second. Then it starts to accelerate and reaches a velocity of 24 met

ers/second in 3 seconds. What’s the acceleration of the motorcycle over this time? Use . 9 m/s2 8 m/s2 6 m/s2 5 m/s2 3 m/s2

2 answers:

Nadya [2.5K]2 years ago

8 0

Answer: 3 m/s^2

Explanation: The acceleration is defined as the rate of change of the velocity:

We know that at the time t = 0 the velocity was 15 m/s

and at the time t = 3s the velocity was 24 m/s

Then the average acceleration may be calculated as the slope of the linear relationship between these two points; this is if the points are (0, 15) and (3, 24)

The slope is : S = (23 - 15)/(3 - 0)m/s^2 = 3m/s^2

So the average acceleration of the motorcycle in this period of time is 3 meters per second squared.

andrew11 [14]2 years ago

4 0

Answer: $3 m/s^2$

Explanation:

The acceleration of the motorcycle is given by

$a=\frac{v-u}{t}$

where

v=24 m/s is the final velocity of the motorcycle

u=15 m/s is the initial velocity

t=3 s is the time taken

Substituting these numbers into the equation, we find

$a=\frac{24 m/s-15 m/s}{3 s}=\frac{9 m/s}{3s}=3 m/s^2$

You might be interested in

. Maria walked 1.5 miles south to her house in 0.5 hours. What is her speed in miles per hour?

Simora [160]

1) 3 miles/Hour

The speed is defined as the distance covered divided by the time taken:

$v=\frac{d}{t}$

where

d = 1.5 mi is the distance

t = 0.5 h is the time taken

Substituting,

$v=\frac{1.5}{0.5}=3 mi/h$

2) 1.34 m/s south

Velocity, instead, is a vector, so it has both a magnitude and a direction. We have:

$d=1.5 mi \cdot 1609 m/mi = 2414 m$ is the displacement in meters

$t=0.5 h \cdot 3600 s/h =1800 s$ is the time taken in seconds

Substituting,

$v=\frac{2414 m}{1800 s}=1.34 m/s$

And the direction of the velocity is the same as the displacement, so it is south.

6 0

3 years ago

For an object starting from rest and accelerating with constant acceleration, distance traveled is proportional to the square of

natali 33 [55]

The problem states that the distance travelled (d) is directly proportional to the square of time (t^2), therefore we can write this in the form of:

d = k t^2

where k is the constant of proportionality in furlongs / s^2

<span>Using the 1st condition where d = 2 furlongs, t = 2 s, we calculate for the value of k:</span>

2 = k (2)^2

k = 2 / 4

k = 0.5 furlongs / s^2

The equation becomes:

d = 0.5 t^2

Now solving for d when t = 4:

d = 0.5 (4)^2

d = 0.5 * 16

<span>d = 8 furlongs</span>

<span>
</span>

<span>It traveled 8 furlongs for the first 4.0 seconds.</span>

8 0

2 years ago

Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 m in Yosemite

german

Answer:

The jumper is in freefall for 12.447 seconds.

Explanation:

Let's start by calculating how far the jumper falls.

Initial height (on cliff) = 910 m

Final height after freefall = 150 m

Distance the jumper falls in freefall = 910 - 150 = 760 m

We can now use the equation of motion below to solve for the time:

$s=u*t+\frac{1}{2} (a*t^2)$

here. acceleration = 9.81 m/s (due to gravity)

initial speed (u) = 0 m/s (because vertical speed is 0 at the start)

and distance (s) = 760 meters (as calculated above)

So for speed we get:

$760=0*t+0.5(9.81*t^2)$

$760=4.905t^2$

t = 12.447 seconds

5 0

3 years ago

Think of a way you could demonstrate elastic force to a younger student. Describe the procedure you would follow and the materia

Soloha48 [4]

Answer:

I feel like to demonstrate you would use an elastic band as the material. You obviously have to put force in order to see how far it stretches. From this you can also find about its resistance and durability

Also you have to make sure the distance between the two hands are equal as you want an accurate result.

7 0

2 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A

ArbitrLikvidat [17]

Answer:

The mass of the solid cylinder is $m = 1612.5 \ kg$

Explanation:

From the question we are told that

The radius of the grinding wheel is $R = 0.330 \ m$

The tangential force is $F_t = 250 \ N$

The angular acceleration is $\alpha = 0.940 \ rad/s^2$

The torque experienced by the wheel is mathematically represented as

$\tau = I * \alpha$

Where I is the moment of inertia

The torque experienced by the wheel can also be mathematically represented as

$\tau = F_t * r$

substituting values

$\tau = 250 * 0.330$

$\tau = 82.5 \ N\cdot m$

So

$82.5 = I * \alpha$

$82.5 = I * 0.940$

So

$I = 87.8 \ kg \cdot m^2$

This moment of inertia can be mathematically evaluated as

$I = \frac{1}{2} * m* r^2$

substituting values

$87.8 = \frac{1}{2} * m* (0.330)^2$

=> $m = 1612.5 \ kg$

5 0

2 years ago