It’s 20+40=60
24+37=60 rounding to the nearest 10 is 60
Let student tickets be s and adult tickets be a. The number of tickets sold of both adult and student then is s + a = 396. If each student ticket costs $3, then we represent the money equation by tacking the dollar amount onto the ticket. 3s is the cost of one student ticket. 4a is the cost of an adult ticket. The total money from the sales of both is 4a + 3s = 1385. We now have a system of equations we can solve for a and s. If s+a=396, then s = 396-a. We will sub that into the second equation to get 4a + 3(396-a) = 1385. Distributing we have 4a+1188-3a=1385. a = 197. That means there were 197 adult tickets sold. If s + a = 396, then s + 197 = 396 and s = 199. 197 adult tickets and 199 student tickets. There you go!
This is the answer this dumb app made me type 20 characters
9514 1404 393
Answer:
- s + a = 250
- 3s + 5a = 1050
Step-by-step explanation:
Let s and a represent the numbers of student and adult tickets sold. The system of equations that can be written from the given information is ...
s + a = 250 . . . . . . total of tickets sold
3s +5a = 1050 . . . dollar value of tickets sold
_____
The solution is (s, a) = (100, 150). 100 student tickets and 150 adult tickets were sold.
Answer:
7/8 estimated would be about 1 and 6/11 is almost a half so it would be estimated 1/2 so 1 - 1/2 = 1/2