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2 years ago

True or False: The relation shown is a function. 20 POINTS!!

Mathematics

1 answer:

elixir [45]2 years ago

4 0

Answer:

True

Step-by-step explanation:

For a relation to be a function each value of x must pair up with one and only one value of

The relation shown is a function.

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Adult tickets to a a basketball game cost $5. Student tickets cost $1. A total of $2,757 was collected on the sale of 1,185 tick

Anastaziya [24]

Answer:

Number of Adults Ticket=393

Number Of Students Tickets=792

Step-by-step explanation:

Let 'x' be the Adult's tickets

Let 'y' be the Student's tickets

x+y=1185 (total sold tickets)

5x+y=2757(total cost of tickets)

-(5x+y=2757)x+y=1185

(-5x-y)- x+y=1185-2757

=-4x+0 = (-1572)

=-4x=(-1572)

x= (-1572)÷-4

=393

=x+y=1185

=393+y=1185

=y=792

So Number of Adults Ticket=393

Number Of Students Tickets=792

Hope it Help

7 0

2 years ago

Find the slope:<br> y = -X – 1

gogolik [260]

Answer:

The slope would be -x

Step-by-step explanation:

The second number in the equations y=mx+b is always the slope unless you have to plug in number and do all kinds of stuff but that's not whats in the problem now.

3 0

2 years ago

Read 2 more answers

When an object moves in a circle the __________ of the object is continually changing. What is the missing word in this sentence

Bezzdna [24]

Answer:

velocity

Step-by-step explanation:

The velocity of the object is continually changing. This velocity is the slope of the tangent line to the curve at a given point on the curve.

3 0

2 years ago

The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui

mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

$s(t) = -16t^2+v_0t+s_0$

Where,

$s_0$ = initial height of the object,

$v_0$ = initial velocity of the object,

Here,

$s_0=400\text{ feet}$

$v_0=35\text{ feet per sec}$

Hence, the height of the ball after t seconds,

$s(t)=-16t^2+35t+400$

When s(t) = 0,

$\implies -16t^2+35t+400=0$

$t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}$

$t=\frac{-35\pm \sqrt{1225+25600}}{-32}$

$\implies t\approx -4.02\text{ or }t\approx 6.21$

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0

2 years ago

In one of its Spring catalogs, L.L. Bean® advertised footwear on 28 of its 192 catalog pages. Suppose we randomly survey 20 page

vichka [17]

100 easy os it correct

8 0

2 years ago