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2 years ago

Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?

Mathematics

1 answer:

BartSMP [9]2 years ago

3 0

Answer:

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

$c^{2} =a^{2} + b^{2}$

Donde c es la hipotenusa y a y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

$15^{2} =12^{2} +b^{2}$

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

$225=144+b^{2} \\225-144=144+b^{2} -144\\81=b^{2} \\\sqrt{81} =b\\9=b$

Por lo tanto, la longitud del otro cateto es 9 cm

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