Step-by-step explanation:
variable is n
operation is addition
constant is 2.35
We have that
x²<span>-6x+7=0
</span>Group terms that contain the same variable
(x²-6x)+7=0
Complete the square Remember to balance the equation
(x²-6x+9-9)+7=0
Rewrite as perfect squares
(x-3)²+7-9=0
(x-3)²-2=0
(x-3)²=2
(x-3)=(+/-)√2
x=(+/-)√2+3
the solutions are
x=√2+3
x=-√2+3
Answer:
yes, the given relation is a function.
Step-by-step explanation:
The given relation is
{(–3, –2), (–1, 0), (1, 0), (5, –2)}
A relation is called function if each element of the domain is paired with exactly one element of the range.
It means for each value of x there exist a unique value of y.
In the given relation for each value of x there exist a unique value of y.
Therefore the required solution is yes and this relation is a function.