Answer:
1.3 M
Explanation:
The question asks to calculate the molarity of a solution.
We have to use the following equitation:
Molarity = # moles / 1 lt of solution
In this case we have a solution composed of 0.65 mol of NaF diluted in a total volume of 0.5 lt. We will have to do the following cross multiplication solving for x:
0.65 mol NaF / 0.5 lt = x mol NaF/ 1 lt
x = 1.3 mol NaF / 1 lt = 1.3 M
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Remember significant figures are all non-zero numbers.
Remark
The balance numbers in front of Ag and AgNO3 are both 2. That number is in moles.
Rule: if the moles are the same in the equation, then whatever you are given for one, will be the same for the other. So you have 0.854 moles of Ag. You will also have 0.854 moles of AgNO3
Answer: 0.854 <<<<<
Answer:
1. Chromium
2. Chlorine.
3. Chlorine.
4. Chromium.
5. 12 electrons.
Explanation:
Hello,
In this case, the given reaction with the appropriate oxidation states turns out:
In such a way, the oxidation half-reaction is written for chromium as the reducing agent so it is oxidized from +3 to +6, nonetheless, since there are two chromiums undergoing such change, 6 electrons are being transferred as shown below:
On the other hand, chlorine's reduction half-reaction as the oxidizing agent result from the transfer of 6 electrons as well from +1 to 0, nonetheless, there are 6 chlorines undergoing such change:
Therefore, there are 12 electrons that are being transferred, 6 for chromium and 6 for chlorine.
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