the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room
1 answer:
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
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Answer:
a) 0.00031
b) 0.0017
c) 0.31
d) 0.00018
Step-by-step explanation:
attached below is the detailed solution
Total number of 7-poker cards are 52P7 = 133784560
A) Determine the probabilities of Seven-card straight
probability of seven-card straight = 0.00031
B) Determine the probability of four cards of one rank and three of a different rank
P( four cards of one rank and three of different rank ) = 0.0017
C) Determine probability of three cards of one rank and two cards of each two different ranks
P( three cards one rank and two cards of two different ranks ) = 0.31
D) Determine probability of two cards of each of three different ranks and a card of a fourth rank
P ( two cards of each of three different ranks and a card of fourth rank ) = 0.00018
