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3 years ago

The marine life store would like to set up fish tanks that contain equal number

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

6 0

Ok that is nice sir 8 is a equal number

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Suppose Felipe has 9.24 pounds of seed if it takes 6.6 pounds of seed to plant on acre of grass how many acres of grass can be p

Lyrx [107]

Answer:

1.4 acres of grass can be planted.

Step-by-step explanation:

He has 9.24 pounds of seeds.

If one acre of grass needs 6.6 pounds of seeds we can divide 9.24 pounds by 6.6 pounds to find how many acres of grass he can plant.

9.24 lbs × $\frac{1acre}{6.6 lbs}$ = 1.4 acres

4 0

2 years ago

Researchers capture and mark 43 squirrels in a park. The next week, researchers capture 50 squirrels and 38 of them are marked f

Vlada [557]

The question is an illustration of sample and population, and the estimate of the population of squirrel in the park is 55

<h3>How to determine the population of squirrel?</h3>

The given parameters are:

Marked squirrels = 43

Captured squirrels = 50

Of the 50 captured squirrels, 38 are from the marked squirrels.

This means that the number of unmarked squirrels is:

Unmarked = 50 - 38

Evaluate

Unmarked = 12

The population of the squirrel is then calculated using:

Population = Marked + Unmarked

So, we have:

Population = 43 + 12

Evaluate the sum

Population = 55

Hence, the estimate of the population of squirrel in the park is 55

Read more about population at:

brainly.com/question/7301139

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6 0

1 year ago

Convert 80 gallons into liters. Round your answer to the nearest whole number.

Alla [95]

2.10 is the answer to the nearest 10th

3 0

1 year ago

Find the general solution of (x+3)y’=2y

gregori [183]

Answer:

$y=C(x+3)^2$

Step-by-step explanation:

We are given:

$\displaystyle (x+3)y^\prime=2y$

Separation of Variables:

$\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}$

So:

$\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx$

Integrate:

$\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx$

Integrate:

$\displaystyle \ln|y|=2\ln|x+3|+C$

Raise both sides to e:

$|y|=e^{2\ln|x+3|+C}$

Simplify:

$|y|=(e^{\ln|x+3|})^2\cdot e^C$

So:

$|y|=C|x+3|^2$

Simplify:

$y=\pm C(x+3)^2=C(x+3)^2$

5 0

2 years ago

Which situation can be represented by the equation below?

pav-90 [236]

Answer:

Where is the equation?

7 0

2 years ago