Acetic acid is 60.05 grams/mole. In 1 liter of vinegar or 1000 ml there would be 0.046% of acetic acid = 46 ml x 1.005g/ml = 46.23 grams/60.05 grams= 0.77 moles per litre of vinegar.This then would be the concentration of acetic acid in for example 1 liter of vinegar.
The total pressure = 1.402 atm
<u><em>calculation</em></u>
Total pressure = partial pressure of gas A + partial pressure of gas B + partial pressure of third gas
partial pressure of gas A= 0.205 atm
Partial pressure of gas B =0.658 atm
partial pressure for third gas is calculated using ideal gas equation
that is PV=nRT where,
p(pressure)=? atm
V(volume) = 8.65 L
n(moles)= 0.200 moles
R(gas constant)=0.0821 L.atm/mol.k
T(temperature) = 11°c into kelvin =11+273 =284 k
make p the subject of the formula by diving both side by V
p =nRT/v
p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm
Total pressure is therefore = 0.205 atm +0.658 atm +0.539 atm
=1.402 atm
Answer:
Density,
Explanation:
It is given that, placing a sample of iron (II) oxide into a graduated cylinder makes the water volume increase 12.0 mL.
It means that the volume of the sample is 12 mL
The weight of the sample is 76.6 g
We need to find the density of the sample.
12 mL = 12 cm³
The formula of density is given by :
So, the density of the sample is .
The number of years that must be invested at a rate of 7 % to earn$ 303.52 in interest is
8 years
<em><u>calculation</u></em>
- <em><u> </u></em><em>by use of the formula A = P (1+ rt) </em>
- <em> where : A is the final amount = 542 + 303.52 =$ 845.52</em>
<em> P is the principal money to be invested = $ 542</em>
<em> r= rate= 7/100=0.07</em>
<em> t= time required</em>
<em>=$ 845.52=$ 542( 1+ 0.07 t)</em>
- <em>open the bracket</em>
- <em>= $845.53= $542 + $37.94 t</em>
- <em>like terms together</em>
=$ 845.53 -$542 = $37.94 t
=$303.52 =$37.94 t
- divide both side by $37.94
= $303.52/ $ 37.94 = $37.94t/$37.94
t= 8 years
Answer:
H2 is Molecular hydrogen. It is a molecule of hydrogen that consists of two hydrogen atoms bonded together by one single bond
Explanation: