cost of pencil = x = 0.07
and cost of eraser = y = 0.03
Step-by-step explanation:
let cost of pencil = x
and cost of eraser = y
So, we have equations:
Solving both equations to find value of x and y
Let:
Multiply eq(1) with 4 and eq(2) with 3 and subtract
Putting value of x in equation 1:
So, x= 0.07 and y = 0.03
cost of pencil = x = 0.07
and cost of eraser = y = 0.03
Keywords: System of equations
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Answer:
James bought 11 good tickets and 5 bad tickets.
Step-by-step explanation:
Given that:
Cost of each good ticket = $8
Cost of each bad ticket = $5
Total amount spent = $113
Total tickets bought = 16
Let,
x be the number of good tickets bought
y be the number of bad tickets bought
x+y=16 Eqn 1
8x+5y=113 Eqn 2
Multiplying Eqn 1 by 5
5(x+y=16)
5x+5y=80 Eqn 3
Subtracting Eqn 3 from Eqn 2
(8x+5y)-(5x+5y)=113-80
8x+5y-5x-5y=33
3x=33
Dividing both sides by 3
Putting x=11 in Eqn 1
11+y=16
y=16-11
y=5
Hence,
James bought 11 good tickets and 5 bad tickets.
Your molarity would be 0.975 M HCl because it’s moles of solute divided by liters of solvent
