Answer:
2x-10
Step-by-step explanation:
Using distributive property:
2 times x = 2x
2 times -5 = -10
5^2 + x^2=8^2
25+x^2=64
X=6.2
If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 
then 
will also be a solution.
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
Subtract 9 from each side of the equation.
m = – 11
Step-by-step explanation:
m + 9 = – 2
To solve the above equation, we simply subtract 9 from each side of the equation.
This is illustrated below:
m + 9 = – 2
Subtract 9 from each side of the equation
m + 9 – 9 = – 2 – 9
m + 0 = – 11
m = – 11
Therefore, the value of m is – 11
