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2 years ago

1. Which of the following appears to cause the temperature of the atmosphere to rise?

Chemistry

1 answer:

Mila [183]2 years ago

7 0

Answer:

increasing level of carbon dioxide

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Chemistry, Lesson 2.6

Orlov [11]

Answer:

the answer is Fructose

Explanation:

the reason is because when it brakes down it forms a sort of fructose

8 0

1 year ago

How many PO43? ions are in a mole of K3PO4?

adoni [48]

K₃PO₄ → 3K⁺ (aq) + PO₄³⁻(aq)

One mole of PO₄³⁻ ion gets dissociated from one mole of K₃PO₄

As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ ions

One mole of PO₄³⁻ ions x (6.022 x 10²³ ions/ 1 mole of PO₄³⁻ ions )

= 6.022 x 10²³ ions

Therefore , there are 6.022 x 10²³ PO₄³⁻ ions in a mole of K₃PO₄.

7 0

2 years ago

If a straight-chain hydrocarbon is a gas at room temperature, how many carbon atoms will it have?

Orlov [11]

The fewer the carbon atoms, the closer it is to being a gas. The only one you have to check out is A which is hexane. You know that gasoline at the pumps has 8 carbons and its a liquid. So B and C are both not gases because they are above 8.

C6 (hexane) is a liquid at room temperature not a gas.

The answer is D. If there is a gas present, it must be C3

6 0

2 years ago

How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol

SVEN [57.7K]

<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u /> $3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} )$ = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

3 0

2 years ago

A researcher dilutes 30.0 ml of ethanol to 300.0 ml with distilled water. what is the percentage concentration by volume of the

Len [333]

Answer: 9.09 %

Explanation:

To calculate the percentage concentration by volume, we use the formula:

$\text{Volume percent of solution}=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100$

Volume of ethanol (solute) = 30 ml

Volume of water (solvent) = 300 ml

Volume of solution= volume of solute + volume of solution = 30+ 300 = 330 ml

Putting values in above equation, we get:

$\text{Volume percent of solution}=\frac{30}{30+300}\times 100=9.09\%$

Hence, the volume percent of solution will be 9.09 %.

3 0

2 years ago

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