The maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.
<h3>What is the range?</h3>
The range is the difference between the maximum and minimum.
Given to us
The standard diameter of a golf ball is 42.67 mm.
The discrepancy in diameter is more than 0.002 mm.
As it is given to us that the standard diameter of the golf ball is 42.67 mm while the discrepancy in diameter is more than 0.002 mm.
Maximum acceptable diameter = 42.67 mm + 0.002 mm = 42.672 mm
Minimum acceptable diameter = 42.67 mm - 0.002 mm = 42.668 mm
Hence, the maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.
Learn more about Range:
brainly.com/question/3507706
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0
Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)
we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c
so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12
split into the + and - for 2 answers
(-7 + 1) / 12
-6/12
-1/2
And
(-7 -1) /12
-8 / 12
-2/3
those are.the 2 answers
But but it says largest so -1/2
Answer:
Wat is the question?
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(3, -1)
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We taking the same final exam
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I don’t know the answer that’s why I came here
