Yes, an example of a molecule would be CO2, which has no dipole moment but does have two polar bonds. Although CO2 has no dipole moment, its charge distribution gives rise to a quadrupole moment
Answer:
THE INITIAL VOLUME OF THE STOCK SOLUTION IS 0.0392 L OR 39.2 mL
Explanation:
To calculate the volume of a solution before dilution, we make use of the dilution formula;
C1 V1 = C2 V2
C1 = the concentration of the stock solution = 15 M
V 1 = the volume of stock solution = ?
C2 = concentartion of final solution = 2.35 M
V2 = volume of final solution = 250 mL = 250/ 1000 = 0.25 L
Rearranging the formula, we obtain;
V1 = C2V2 / C1
V 1 = 2.35 * 0.25 / 15
V1 = 0.5875 / 15
V1 = 0.0392 L
the initial volume of the stock solution is 0.0392 L or 39.2 mL
<span>According to the law of conservation of mass, the masses of the products and reactants must be the same. Adding calcium to the product side is considered a mistake if it is not in the reactant side of a particular chemical equation because it is impossible to produce calcium from thin air (unless this is a nuclear reaction).</span>
