Pretty sure it’s 16TXI, hope this helps!
(x + y)^2 = (x^2 - 2xy + y^2)
First distribute the ^2 on the left side of the equation to each term inside the parenthesis:
x^2+ 2xy + y^2
Now pick one of the variables to solve for and isolate it:
(solving for x)
x^2 + 2xy + y^2 = x^2 - 2xy + y^2
x^2+ 2xy = x^2 - 2xy
2xy = -2xy
-x = x
x = 0
When you solve for y in the equation it will turn out to be 0 as well
Hey there!
1/7 ÷ 2
= 1/7 ÷ 2/1
1/7 ÷ 2/1
Revert 2/1 to 1/2
1 × 1 / 7 × 2
1 × 1 = 1 ⬅ your NUMERATOR (top number)
7 × 2 = 14 ⬅ your DENOMINATOR (bottom number)
1(1) / 7(2) = 1/14
Answer: 1/14 ✅
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
Answer:
ab
Step-by-step explanation:
Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
As h approaches 0 from the positive side, then:
Thus, f'(c) = 0