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2 years ago

Please help me this is 50% of my grade

Mathematics

1 answer:

Lerok [7]2 years ago

7 0

its A

because 2.26 x 2.7 = 6.102 which is closest to 6

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A set of pulleys is used to lift a piano with a mass of 102 kg. The piano is lifted 3 meters in 1 minutes. How much power is use

agasfer [191]

Answer:

50.031 watts

Step-by-step explanation:

Formula

Power = Force * distance / time

The units are critical

distance = meters

time = seconds

force = newtons = kg * m / s^2

Solution

F = m * a

a = 9.81

m = 102 kg

F = 102 * 9.81 = 1000.62 Newtons

T = minute = 60 sec/min * 1 min

T = 60 seconds

d = 3 meters

Power = 1000.62 * 3 / 60

Power = 50.031

3 0

2 years ago

4 (5x-3) -64 (3-x) -3 (12x-4)=96

Yuki888 [10]

Are you trying to simply the equation if so x = 6

4 0

2 years ago

Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

$f''(x) = 20 {x}^{3} - 6x$

$f''( - \frac{ \sqrt{15} }{5} ) \: < \: 0$

Hence

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} + 750))$

is a maximum point.

$f''( \frac{ \sqrt{15} }{5} ) \: > \: 0$

Hence

$( \frac{ \sqrt{15} }{5} , \frac{1}{125} (- 6 \sqrt{15} + 750))$

is a minimum point.

$f''(0) \: =\: 0$

Hence (0,-6) is a point of inflexion

4 0

2 years ago

Write the equation of the line MN, which is formed by the points M(-3,5) and N(2,0)

belka [17]

The equation is <span>y = -x + 2</span>

3 0

2 years ago

Read 2 more answers

What is the circumstance of the trampoline including its outer edge? Use 3.14 for pie

Lubov Fominskaja [6]

Answer:

c = 43.96

Step-by-step explanation:

First you have to find the diameter of the trampoline which would be 14

Next plug it into the circumference formula c = dπ

c = (14)(3.14)

c = 43.96

7 0

2 years ago