Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Answer:
Ur answer is D. They should grow native plants on the lodging property to attract local wildlife.
Explanation:
Hope this helps :). Have a great day!
Answer:
Option (a) and (d).
Explanation:
The breaks in DNA molecule may occur due to replication error and oxidizing agent. The double-stranded breaks in DNA can be corrected by Homologous end joining and non homologous end joining.
Homologous end joining is used to repair the DNA present in G2 nad S phases of the cell cycle. The homologous sequences of DNA is used to repair the DNA. Non homologous end joining occurs in the cell present at G0 and G1 phase of the cell cycle. The DNA broken ends are juxtaposed and later rejoin together by DNA ligase.
Thus, the correct answer is option (a) and (d).
C) I and III only just got this question on usa test prep and therefore i'm right
Timothy does not get a promotion at work because he has cancer is an example of genetic discrimination.
Explanation:
Genetic discrimination is termed so when an employer or an insurance company treats indifferently an individual with gene mutation or heritable diseases.
The act of not giving promotion and using the genetic information for the reason by the employer is indifferent and termed genetic discrimination as in case of cancer where life expectancy and large insurance claim is the reason.
Insurance companies do not give benefits or insurance to potential people having or prone for having the mutation and heredity disease.
To help overcome this discrimination federal level laws have been implemented as Genetic information non discrimination act. It strictly prohibits the indifferent behaviour of the employers and insurance companies.
