All categories

2 years ago

Find the zero of a function for n(x)= -6x+18, please show your work.

Mathematics

1 answer:

Elenna [48]2 years ago

4 0

Answer:

Step-by-step explanation:

Find the value of x for which n(x) = 0.

-6x+18 = 0

6x = 18

x = 3

You might be interested in

Set up the equation to find the AREA of the SMALL rectangle with a length of (x) and width (x+7)

Igoryamba

<u>Answer:</u>

<u>Step-by-step explanation:</u>

To find the area of a rectangle, we have to multiply the length with the width.

In the question, the given length is 'x' and the width given is 'x +7'

So, the area would be

( $x$ ) x ( $x + 7$ )

The area = $x^{2} + 7x$

So, the equation to find the area of such a rectangle would be:-

( $x$ ) x ( $x + 7$ )

7 0

2 years ago

The picture shows a triangular island:

sergiy2304 [10]

Answer:

The expressions that show the value of q are

1) $q=\sqrt{r^{2}+s^{2}}$

2) $q=\frac{s}{cos(55\°)}$

3) $q=\frac{r}{sin(55\°)}$

4) $q=\frac{s}{sin(35\°)}$

5) $q=\frac{r}{cos(35\°)}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

case A)

In the right triangle of the figure

Applying the Pythagoras Theorem

$q^{2}=r^{2}+s^{2}$

$q=\sqrt{r^{2}+s^{2}}$

case B)

In the right triangle of the figure

$cos(55\°)=\frac{s}{q}$

solve for q

$q=\frac{s}{cos(55\°)}$

case C)

In the right triangle of the figure

$sin(55\°)=\frac{r}{q}$

solve for q

$q=\frac{r}{sin(55\°)}$

case D)

In a right triangle

if $A+B=90\°$

then

$cos(A)=sin(B)$

therefore

$q=\frac{s}{cos(55\°)}$ ------> $q=\frac{s}{sin(35\°)}$

$q=\frac{r}{sin(55\°)}$ ------> $q=\frac{r}{cos(35\°)}$

4 0

2 years ago

Read 2 more answers

What’s the correct answer for this?

makkiz [27]

Answer:

PO = 36

Step-by-step explanation:

Since both the chords are equal in length so they must be equidistant from the centre.

And

PG = GO

-x+10 = -3(x+2)

-x+10 = -3x-6

-x+3x = -6-10

2x = -16

Dividing both sides by 2

x = -8

Now

PO = PG + GO

PO = -(-8)+10+(-3)((-8)+2)

PO = 8+10+(-3)(-6)

PO = 18+18

PO = 36

8 0

2 years ago

(I NEED HELP ASAP)Edna has a segment with endpoints F(4, 9) and G(7, 2) that is divided by a point H such that FH and GH form a

jeyben [28]

Answer:

1/4 is your answer.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

If g(x) = x squared − 4, find g(5).

Ksenya-84 [330]

G(5)= 5 squared which is 25 minus 4 is 21

5 0

2 years ago