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2 years ago

Question 8 Multiple Choice Worth 1 points)

Mathematics

1 answer:

satela [25.4K]2 years ago

7 0

Answer:

cos 0=90 degrees

Step-by-step explanation:

If sin of 90 is 1 then cos 90 is 0. Since sin and cos are like complementary angles they angles add up to 90 degrees.

$\sin(90) = \cos(0)$

and since sin 90 equal 1 cos of 0 equal 1.

What if we switch angles

Well they are still equal

$\sin(0) = \cos(90)$

But this time sin of 0 is 0 and cos 90 is 0.

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<h3>Solution:</h3>

$\rightarrow\sf((p(x) {x}^{2} + 2x + 4)( {x}^{2} + 2x + 4)) \\ = \sf {ax}^{2} + bx + c \\ = \sf(p(x) {x}^{2} {x}^{2} + p(x) {x}^{2} (2x) + p(x) {x}^{2} \times 4 + 2x \times {x}^{2} + 2x(2x) + 2x \times 4 + {4x}^{2} + 4(2x) + 4 \times 4) \\ = \sf( {x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16) \\ \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

<h3>Answer:</h3>

$\large\boxed{\sf{\red{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}$

$\color{red}{==========================}$

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