Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
5x - 18 + x = 90
6x = 108
x = 18 degrees
Answer:
case a) ----> open up
case b) ----> open down
case c) ----> open left
case d) ----> open right
Step-by-step explanation:
we know that
1) The general equation of a vertical parabola is equal to
where
a is a coefficient
(h,k) is the vertex
If a>0 ----> the parabola open upward and the vertex is a minimum
If a<0 ----> the parabola open downward and the vertex is a maximum
2) The general equation of a horizontal parabola is equal to
where
a is a coefficient
(h,k) is the vertex
If a>0 ----> the parabola open to the right
If a<0 ----> the parabola open to the left
Verify each case
case a) we have
so
so
therefore
The parabola open up
case b) we have
so
therefore
The parabola open down
case c) we have
so
therefore
The parabola open to the left
case d) we have
so
therefore
The parabola open to the right
Answer:
20.60000000000
Step-by-step explanation: