The ticket price that would maximize the total revenue would be $ 23.
Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:
- 20,000 x 30 + 20,000 x 8 = 760,000
- 24,000 x 25 + 24,000 x 8 = 792,000
- 28,000 x 20 + 28,000 x 8 = 784,000
- 26,000 x 22.5 + 26,000 x 8 = 793,000
- 27,200 x 21 + 27,200 x 8 = 788,000
- 26,400 x 22 + 26,400 x 8 = 792,000
- 25,600 x 23 + 25,600 x 8 = 793,600
- 24,800 x 24 + 24,600 x 8 = 792,000
Therefore, the ticket price that would maximize the total revenue would be $ 23.
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Sale price = $450
original price = 25%y
dicount = +20%
solution = $450 × 45%
= $202.5
= $652.5
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The base is 6 so you'll need to replace b with 6 and the height is 8 so you'll need to replace h with 8.
Problem 16 Begin by setting corresponding positions equal to each other.
9 = x + 2y and 13 = 4x + 1
The second equation only has one variable so you should solve it first.
13 = 4x + 1
13 - 1 = 4x + 1 - 1
12 = 4x (divide both sides by 4)
3 = x
you can use this value to find y in the other equation
9 = 3 + 2y
9 - 3 = 3 - 3 + 2y
6 = 2y
3 = y
For this case we must simplify the following expression:
So, we have:
We apply double C:
We simplify:
Answer:
The simplified expression is: