Answer:
The correct answer is 532 K
Explanation:
The Gay-Lussac law describes the behavior of a gas at constant volume, by changing the pressure or temperature. When is heated, the change in pressure of the gas is directly proportional to it absolute temperature (in Kelvin or K).
We have the following initial conditions:
P1= 71.8 kPa
T1= -104ºC +273 = 169 K
If the pressure increases until reaching 225.9 kPa (P2), we can calculate the final temperature of the gas (T2) by using the Gay-Lussac derived expression:
P1 x T2 = P2 x T1
⇒T2= (P2 x T1)/P1 = (225.9 kPa x 169 K)/71.8 kPa= 531.7 K ≅ 532 K
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Answer
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Answer:
ΔH(mix'g)= 42.3Kj/mole
Explanation:
ΔH = (mcΔT)water/moles X
m = mass(g) = 20ml x 1.00g/ml = 20 g
c = 4.184 j/g⁰C
ΔT = 25°C- 15°C = 10°C
moles X = (1.5g)/(76g/mole) = 0.0197 mole X
ΔH = (20g)(4.184j/g°C)(10°C)/(0.0197 mole X) = 42,300J/mole = 42.3Kj/mole (3 sig.figs.)